Solve the following pair of linear equations | vedclass

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(B) Given the equations: $1) \ 2x + 3y = 12$ $2) \ 2x + 3y = 6$ Comparing these equations with the standard form $a_1x + b_1y + c_1 = 0$ and $a_2x + b

Vedclass · Accepted Answer

$\varnothing$ (No solution)

Vedclass · Answer

(B) Given the equations: $1) \ 2x + 3y = 12$ $2) \ 2x + 3y = 6$ Comparing these equations with the standard form $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$,we have: $a_1 = 2, b_1 = 3, c_1 = -12$ $a_2 = 2, b_2 = 3, c_2 = -6$ Calculating the ratios: $\frac{a_1}{a_2} = \frac{2}{2} = 1$ $\frac{b_1}{b_2} = \frac{3}{3} = 1$ $\frac{c_1}{c_2} = \frac{-12}{-6} = 2$ Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines are parallel to each other. Parallel lines do not intersect at any point,which means the system of equations has no solution. Therefore,the solution set is $\varnothing$.

Solve the following pair of linear equations in two variables graphically: $2x + 3y = 12$ and $2x + 3y = 6$.

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